In basketball, players often take free throws. When Michael takes his first free throw in any game, the probability that he is successful is 0·7. For all subsequent free throws in the game, the probability of success is 0·8 if he was successful on the previous throw, and 0·6 if he was unsuccessful on the previous throw.
(a)Find the probability that Michael is successful (S) with all three of his first three free throws in a game, P(S, S, S).
(b)Find the probability that Michael is unsuccessful (U) with his first two free throws and successful with the third, P(U, U, S).
(c)List all the ways that Michael could be successful with his third free throw in a game and hence find the probability that Michael is successful with his third free throw.
(d)(i)Let pn be the probability that Michael is successful with his nth free throw (so 1 − pn is the probability of being unsuccessful). Show that pn+1 = 0·6 + 0·2pn.
(ii)Assume that p is Michael's success rate in the long run; that is, for large n, pn+1 ≈ pn ≈ p. Using the result from (d)(i), or otherwise, show that p = 0·75.
(e)(i)For all positive integers n, let an = p − pn, where p = 0·75. Use the ratio an+1/an to show that an is a geometric sequence with common ratio 15.
(ii)Find the smallest value of n for which p − pn < 0·00001.
(f)(i)You arrive at a game in which Michael is playing. You know he has already taken many free throws, but you do not know his pattern of success. Based on this, what is your estimate of the probability that Michael will be successful with his next free throw?
(ii)Why would it not be appropriate to consider Michael's subsequent free throws in the game as a sequence of Bernoulli trials?